Post: failed the class :(
Options
12-02-2015, 05:32 PM
#1
HeroWin
Java Developer
ITS IN JAVA
Exactly one of these code fragments calculates the sum of the integers from 1 through 9. Which one?
A
int n = 9;
int sum = 0;
while ( n > 1 )
{
sum += n;
}
B
int n = 9;
int sum = 0;
while ( n > 1 )
{
n--;
sum += n;
}
C
int n = 0;
int sum = 0;
while ( n < 9 )
{
sum += n;
n++;
}
D
int n = 9;
int sum = 0;
while ( n > 0 )
{
sum += n;
n--;
}
E
int n = 0;
int sum = 0;
while ( n <= 9 )
{
n++;
sum += n;
}
12-03-2015, 12:38 AM
#2
Trefad
I defeated!
Originally posted by HeroWin
i failed a class because i was one question off and this was the question... please explain the answer as to why its D... i dont get why
ITS IN JAVA
ITS IN JAVA
Exactly one of these code fragments calculates the sum of the integers from 1 through 9. Which one?
A
int n = 9;
int sum = 0;
while ( n > 1 )
{
sum += n;
}
B
int n = 9;
int sum = 0;
while ( n > 1 )
{
n--;
sum += n;
}
C
int n = 0;
int sum = 0;
while ( n < 9 )
{
sum += n;
n++;
}
D
int n = 9;
int sum = 0;
while ( n > 0 )
{
sum += n;
n--;
}
E
int n = 0;
int sum = 0;
while ( n <= 9 )
{
n++;
sum += n;
}
Since sum's value is 0, += n makes sum add to 9 since n = 9. Then n is subtracted by one by using n-- (I'm not sure why it's subtracted). This is a loop. While n is less than 0 it loops.
12-04-2015, 09:59 AM
#3
Winter
Purple God
Originally posted by Trefad
Since sum's value is 0, += n makes sum add to 9 since n = 9. Then n is subtracted by one by using n-- (I'm not sure why it's subtracted). This is a loop. While n is less than 0 it loops.
You answered your own question within your answer. It's subtracted because the loop would go on forever otherwise.
Originally posted by HeroWin
i failed a class because i was one question off and this was the question... please explain the answer as to why its D... i dont get why
ITS IN JAVA
ITS IN JAVA
Exactly one of these code fragments calculates the sum of the integers from 1 through 9. Which one?
A
int n = 9;
int sum = 0;
while ( n > 1 )
{
sum += n;
}
B
int n = 9;
int sum = 0;
while ( n > 1 )
{
n--;
sum += n;
}
C
int n = 0;
int sum = 0;
while ( n < 9 )
{
sum += n;
n++;
}
D
int n = 9;
int sum = 0;
while ( n > 0 )
{
sum += n;
n--;
}
E
int n = 0;
int sum = 0;
while ( n <= 9 )
{
n++;
sum += n;
}
N equals 9
SUM equals 0
while N does NOT equal 0
add N to SUM
subtract 1 from N
code-wording helps people who can't visualize the effect of code.
The following user thanked Winter for this useful post:
12-04-2015, 08:47 PM
#4
vRice
Haxor!
Originally posted by Trefad
Since sum's value is 0, += n makes sum add to 9 since n = 9. Then n is subtracted by one by using n-- (I'm not sure why it's subtracted). This is a loop. While n is less than 0 it loops.
I would say it's because it's less stress on the CPU/more efficient to decrement, but I'm not sure if that's only for loops
The following user thanked vRice for this useful post:
12-05-2015, 06:23 PM
#5
Red-EyeX32
AstroCFG
Originally posted by HeroWin
i failed a class because i was one question off and this was the question... please explain the answer as to why its D... i dont get why
ITS IN JAVA
ITS IN JAVA
Exactly one of these code fragments calculates the sum of the integers from 1 through 9. Which one?
A
int n = 9;
int sum = 0;
while ( n > 1 )
{
sum += n;
}
B
int n = 9;
int sum = 0;
while ( n > 1 )
{
n--;
sum += n;
}
C
int n = 0;
int sum = 0;
while ( n < 9 )
{
sum += n;
n++;
}
D
int n = 9;
int sum = 0;
while ( n > 0 )
{
sum += n;
n--;
}
E
int n = 0;
int sum = 0;
while ( n <= 9 )
{
n++;
sum += n;
}
The rest of the loops are starting from different integers, just remember that it always start from 0. Otherwise, it would be wrong.
Copyright © 2024, NextGenUpdate.
All Rights Reserved.
