(adsbygoogle = window.adsbygoogle || []).push({}); To read memory from a particular memory address IF allocated:

    char* readMem(DWORD address, unsigned int count)

{

	char* addr = (char*)address;				//convert the address to a char*

	char* newAddr = new char[count];			//instansiate a new char* to hold the data from that address

	for(unsigned int x = 0;x<count;++x)

		newAddr[x] = addr[x];					//fill the array

	return newAddr;

}

Does anyone know what this is or does?...

Looks at the memory address given and adds from that memory address onwards the memory to the char array.

Let me take a shot, you point to the memory location given, then you take the data that is pointed to and assign it to a char. Then you fill an array with the amount of data the user wants by going up in memory adresses. Then you return the actual data that is there in the form of an array?

Note:
I thought you could only access memory that your application owned.. Or does that only apply for the app's stack? Can you access the heap or "Free Store" at any location?

dont you have to delete the char array since you initialized it with the keyword new?

You can access any memory as long as it has been allocated/malloc'd.

---------- Post added at 03:06 PM ---------- Previous post was at 03:01 PM ----------



A little bit of excess memory doesn't hurt. But in your code, you would do:

    typedef unsigned long long DWORD;

//-------------------------------------------------

DWORD address = 0x1A;

char* dataAtMem = readMem(address, 2);

free(&(dataAtMem*)); //That might be wrong, but you just call the free method.

//free(*(dataAtMem*)); Might be the right way, don't have compiler open to test atm.

So yeah. This code is just for reading, the memory management is your task

Can you write it though?

how many years have you been programming

yes.

&address = (char*)0xEE; //your data here.