(adsbygoogle = window.adsbygoogle || []).push({}); hw do ppl still nt understand how to do this, took this from another thread but needs to be at the top of a thread





Get CoD Tool, I have 1.5, works great. (i use 1.42)
Then load your WaW gamesave into CoD tool.
Go to the advanced tab, and enter codes TWICE!!!
Like player_LastStandBleedoutTime Then put the value as like 300 (6 mins)
Or player_clipsizemultiplier then value 999, over 1000 ****s the game up.
Another cool one is g_knockback then value 99999 or whatever,
Theres a full list somewhere here, or just google it

But remember you must put them like this..

g_knockback 99999
g_knockback 99999

Then load up WaW > Solo > Resume Game > Save and quit
Co-op Campain > Private Match (You must host) > Invite friends!

NOTE: These will work for friends except things like player_laserForceOn 1
I think thats laser sight, hope I helped.

And use correct grammar when posting, its especially, not especually!

he frogot the a its bruva it means brother in like txt or stuff

I know what it means. I'm trying to imply that he should stop thinking he's cool and type like a normal person.

well dont make a big deal people are never like another person

Sorry but you just leached. Said to everyone use REAL ENGLISH/GRAMMAR.

and you are like, 'Bruv yh i will bang u step back and jab u again coz i lyk ate totenam and i have some fagit names like w8yids man so yh i is like some bad ass charva BLUD'

^^ that's you cause your black.

wot u racist, i write like this cos its quicker not cos im thick or i think im a gangster. nd y u cummin in here running your mouths off when i put i found in a different thread. dnt say cos da rep

Ok.....

So I have to put these codes in twice? (i have v1.5 Beta 2)

and then get invited to a game by a friend while i'm sitting on the dashboard?

P.S: Whats the highest value for knockback?

were did you get 1.5 beta 2 ?
x Gilder

Any more flame or arguments and this thread will have to be closed

Let's keep arguing, this thread deserves to be closed as there's already another one.